Thermodynamics: Calculating total resistance of window

AI Thread Summary
The discussion focuses on calculating the total thermal resistance of a triple glazed window consisting of three glass panes and two air cavities. The thermal conductivities of the materials are provided, with the glass at 0.8 W•m-1•K-1 and air at 0.028 W•m-1•K-1. The correct approach involves considering conduction through the glass panes and convection through the air gaps, although convection may be negligible due to the small thickness of the air gaps. A participant points out a potential error in calculating the resistance of the air gaps, suggesting the thickness was mistakenly taken as 1m instead of 12mm. The overall goal is to determine the total thermal resistance accurately, which is expected to be 1 KW.
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Homework Statement


A triple glazed window consists of 3 clear glass panes of 3 mm thickness each, separated by air cavities of 12 mm each. The window area is 1.0 m2 . If the thermal conductivity of the glass panes is 0.8 W•m-1•K-1 and of the air cavities is 0.028 W•m-1•K-1 what is the total thermal resistance of the window?

Homework Equations

The Attempt at a Solution


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The correct answer is meant to be 1 KW. I was initially going to do something with the internal air and external air but the question says the total thermal resistance of the window. So it should be conduction1 through the first pane of glass, then convection1 through first air gap then conduction2 through second glass pane then convection2 through second air gap then finally conduction3 thorugh third glass pane.
 
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I think the air gaps are small enough for convection to be ignored?

In your working, where you calculate the resistance of the air gaps... You appear to have the thickness as 1m rather than 12mm?
 
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