Thermodynamics: Cooling Superheated Water Vapor to Saturated Vapor

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The discussion revolves around cooling superheated water vapor at 400 kPa until it reaches a temperature of 115°C, marking the onset of condensation. The saturated vapor conditions at this point are identified as 115°C and 169.18 kPa. Participants explore whether the initial temperature of the superheated vapor can be determined using the pressure and temperature relationship, specifically the ratio P1/T1 = P2/T2. It is suggested to verify if the ideal gas assumptions hold for water in this scenario, considering the constant density of the vapor. Additionally, alternative methods such as using steam tables or corresponding states information are recommended for more accurate calculations.
afpskierx
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Superheated H20 at 400 kPa is slowly cooled in a sealed rigid vessel until the temperature is measured to be 115 centigrade, when condensation first occurs.

What is the Initial Temperature?

I know that the temperature and pressure at point two (saturated vapor) can be found in a standard saturated water vapor table. I found Tsat and Psat to be 115 Centigrade and 169.18 kPa respectively.

Is there enough information here to find the initial temperature of the superheated vapor? how do I proceed?
 
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Is it a simple ratio of the Pressure and Temperature at each point?

i.e. P1/T1=P2/T2 ?
 
afpskierx said:
Is it a simple ratio of the Pressure and Temperature at each point?

i.e. P1/T1=P2/T2 ?

Sure, but please check to make sure you are in the ideal gas region for water. The molar density is a constant in this problem (as is, of course, to mass density). You may be able to follow a constant density line for water on a published graph, or in the steam tables (I don't remember whether the steam tables give constant density data, although they probably don't). You can also use corresponding states info, virial equation parameters, or van der waals parameters to correct for non-ideal behavior, if that turns out to be significant.
 
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