Thermodynamics: Internal Energy of a Gas

AI Thread Summary
The discussion revolves around calculating the internal energy of helium gas in a container and determining how long a 0.38-hp engine must run to produce that energy. The relevant equations include the ideal gas law (PV = nRT) and the internal energy formula for a monatomic gas (U = 3/2 nRT). The user initially calculated the internal energy as 9300 J and derived a power output of 290.32 W, leading to an incorrect time estimate. After recalculating, they found the correct time to be approximately 32 seconds. The user confirmed the final calculation was accurate with assistance from others in the forum.
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Homework Statement


Helium (He), a monatomic gas, fills a 0.010-m^3 container. The pressure of the gas is 6.2 multiplied by 10^5 Pa. How long would a 0.38-hp engine have to run (1 hp = 746 W) to produce an amount of energy equal to the internal energy of this gas?



Homework Equations




Equations: DU = Q + W , Possibly PV = nRT?, Possibly DU = 3/2 n R T ?

The Attempt at a Solution


No idea how to go about doing this.
 
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Use PV = nRT and U = 3/2nRTtherefore U=3/2(PV).R.
 
Last edited:
So using that, I get U = 9300J,
P= 290.32 W,
So how do I find the time?
Thanks.
 
Do you know how power and energy are related to each other?

Or, more simply, what is power?
 
Power = work / time
I substituted in, got 23 seconds, and that is not the right answer...
am I doing something wrong?
 
My power is 283.48W,
which gives t=32.8 s.
 
I redid it and I got 32.08. I think I missed a decimal?
Thanks for the help... i'll try that.

EDIT: Yup it worked! Thanks very much :)
 
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