Thermodynamics -- mono and diatomic gases

AI Thread Summary
The discussion focuses on the thermodynamic properties of monoatomic and diatomic gases, specifically their molar heat capacities at constant volume and pressure. The molar heat capacity for monoatomic gases is identified as 3/2R, while for diatomic gases it is 7/2R. It is noted that the heat capacity at constant pressure (Cp) can be calculated as Cp = R + Cv. The conclusion drawn is that the processes involving monoatomic gases will result in higher temperatures compared to those involving diatomic gases, leading to the identification of processes 1 and 3 as monoatomic and 2 and 4 as diatomic. The discussion emphasizes the relationship between heat capacity and temperature change in these gases.
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Homework Statement


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The 4 processes involve one mole of either mono- or di-atomic gas with the same amount of heat (absorbed or discharged)

•Which belong to the mono and which to the diatomic gas?

Homework Equations


i don't know which equations I should use and how start solving it..
I started thinking by taking into consideration the degrees of freedom of each but it didn't work
 
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What is the molar heat capacity at constant volume for a monoatomic gas? What is the molar heat capactiy at constant volume for a diatomic gas?
 
Chestermiller said:
What is the molar heat capacity at constant volume for a monoatomic gas? What is the molar heat capactiy at constant volume for a diatomic gas?
(molar heat capacity at constant volume=f/2 R where f is then number of degrees of freedom) I think it should be 3/2R for monoatomic and 7/2Rfor diatomic and delta T is inversly proportional to heat capacity. Similarly for heat capacity at constant pressure (Cp=R+Cv) so diatomic will get a lower temprature than monoatomic ones so 1,3 monoatomic and 2,4 diatomic
Correct?
 

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