# Thermodynamics: Unsteady Flow (Charging) Process

1. Oct 29, 2012

### afpskierx

I am not sure how to proceed. I do not know Mi or M2, nor do I have enough information to determine the temperature at point two (when the valve is closed). Any help getting me going along will be much appreciated. :)

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2. Oct 29, 2012

### emKhairol

Hi afpskierx,

Have you find the $u_2$ by doing interpolation? I got the answer for $u_2$ = 3047.35 kJ/kg

At state 1, I don't quite understand with the question which stated that that mass of saturated mixture of water is 12kg.

So, I assume the quality, x = mass of vapour / total mass. You will get 7.2kg for your mass of vapour.

At state 2 (which is the $P_2$ = 400kPa and $T_2$ = 450 C) I assume it SUPERHEATED VAPOUR seems the $T_2$ larger than saturated temperature.

I just can help for what I wrote above. Otherwise, I'll try come out for the full solution later.

3. Oct 29, 2012

### afpskierx

What did you use to look up u2? The only thing we know about it is that its quality is one (it is a saturated vapor).

4. Oct 29, 2012

### emKhairol

can you PM me your e-mail address? I'll send to you slides for your reference. Thanks :)