Thermodynamics !

  • #1
The question gives a picture of a brayton cycle with temperature on the x-axis and pressure on the y-axis. It is for the monatomic gas, helium, and we are told that there are two moles. The diagram consists of two adiabatic processes and two isobaris processes. You are given two temparatures and the asked to find the other two. I did that just fine. However, then it asks you to find the heat flow (delta Q) per kilogram of helium for the entire cycle. I know that delta Q of adiabatic processes are 0, so I would only have to worry about the isobaric processes. I know that for the isobaric parts, the delta Q will be equal to n*Cp*change in temperature. So, to find the heat flow per kilogram, would I simply just say that since there are 250 moles in 1 kg of helium, I could use 250 moles/kg for n in the equation? I would appreciate any help!
 

Answers and Replies

  • #2
Andrew Mason
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sportsrules said:
I know that for the isobaric parts, the delta Q will be equal to n*Cp*change in temperature. So, to find the heat flow per kilogram, would I simply just say that since there are 250 moles in 1 kg of helium, I could use 250 moles/kg for n in the equation?
Yes.

AM
 

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