Thin conducting plate boundary conditions

nutan123
Messages
2
Reaction score
0

Homework Statement



A thin conductor plate is in free space. Its conductivity is finite and thickness is approaching zero. Relate the tangential electric field in either side of the conductor. Repeat for tangential magnetic field. How are electric and magnetic fields related.

Homework Equations


Standard boundary conditions
\textbf{n}*(\textbf{h2}-\textbf{h1})=\rho
\textbf{n}*(\textbf{e2}-\textbf{e1})=0


The Attempt at a Solution


Tried to apply the boundary conditions on each of the boundries. However, could not relate the field from both the sides.
 
Physics news on Phys.org
nutan123 said:

Homework Statement



A thin conductor plate is in free space. Its conductivity is finite and thickness is approaching zero. Relate the tangential electric field in either side of the conductor. Repeat for tangential magnetic field. How are electric and magnetic fields related.

Are you given any other information, such as the free charge density or free current density on the plate?

Homework Equations


Standard boundary conditions
\textbf{n}*(\textbf{h2}-\textbf{h1})=\rho
\textbf{n}*(\textbf{e2}-\textbf{e1})=0

Those are not standard boundary conditions. Assuming \textbf{n} represents the surface unit normal, \textbf{n}\cdot\left(\textbf{E}_2-\textbf{E}_1\right) and \textbf{n}\cdot\left(\textbf{H}_2-\textbf{H}_1\right) represent difference in the normal components of the fields...you are asked to relate the tangential components of the fields.

In any case, \textbf{n}\cdot\left(\textbf{H}_2-\textbf{H}_1\right)\neq\rho (I assume \rho is supposed to represent the free surface charge density?) and \textbf{n}\cdot\left(\textbf{E}_2-\textbf{E}_1\right)\neq 0 in general.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top