Thin Film Interference in Glass Plates: How Many Bright Fringes Will Be Seen?

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SUMMARY

The discussion focuses on calculating the number of bright fringes observed in a thin film interference scenario involving two glass plates separated by a wire. The light wavelength is specified as 683 nm, and the plates are 120 mm long with a separation ranging from 0 mm to 0.048 mm. The optical path difference is crucial for determining constructive interference, represented by the equation 2naird = mλ, where m is the order of the fringe. The finite size of the plates limits the number of observable fringes.

PREREQUISITES
  • Understanding of thin film interference principles
  • Familiarity with Snell's Law
  • Knowledge of optical path difference calculations
  • Basic concepts of constructive and destructive interference
NEXT STEPS
  • Study the derivation of the optical path difference in thin films
  • Learn about the conditions for constructive interference in thin films
  • Explore the effects of varying film thickness on interference patterns
  • Investigate practical applications of thin film interference in optics
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Students and educators in physics, particularly those focusing on optics, as well as researchers and professionals working with optical devices and interference patterns.

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Homework Statement



A broad beam of light, of wavelength 683nm is sent directly down through the top plate of a pair of glass plates. The plates are 120mm long, touch at the left end and are separated by a wire of a diameter .048mm at the right end. Air between the plates act as a thin film. How many bright fringes will be seen by an observer looking down through the top plate?

Homework Equations



Perhaps Snell's Law
Perhaps a calculation for the optical path difference.

The Attempt at a Solution



I am really just not sure where to start with this. I have been plagued by these types of optics questions for a while. I think I basically have to calculate the Optical path difference and that will account for either constructive or destructive interference of the light, with an appropriate wavelength multiple added on to it.

I am not sure why there would be a limit on the number bright fringes seen by the observer looking down at the plates. I guess that is due to the finite size of the plate.

Is it just,
$$2n_{\text{air}}d=m\lambda$$
and solve for m? If so, why?
 
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I think I need to do an integration summing up the m's for all the values of d. Because the plates go from 0mm separation to .048 mm separation.
 

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