Three Charges Aligned on a Straight Wire

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The discussion revolves around determining the position of a -1.5q3 charge along a straight wire to ensure the total electric field at the midpoint (P) is zero. The positive charge (q1) at the origin and the negative charge (q2) at 2L create electric fields in the positive x direction, necessitating the placement of the -3/2q3 charge to the left of P to counteract these fields. The equation Etotal = 1/4πεo { E1 + E2 - E3 } = 0 is set up to find the distance x from the origin. Participants express confusion over charge notation and the multiple solutions for x that arise from solving the equation. The thread highlights the challenges of visualizing and solving this seemingly straightforward 1D problem.
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Three charges are aligned along a straight wire as show.
+C ?<--- -3/2 C --->? -C
+ q1 -3/2 q3 - q2
X----------------------------o-----------------------------X
P(midpoint)
|---------------------------- L-----------------------------2L
x=0 -----> +x

Assume that the +q1 charge is situated at the origin and the -q2 charge is located at distance 2L from the origin. Determine the distance that the -1.5q3 charge is from the origin in order that the total electric field at the midpoint of the wire vanishes.

Of course we have the positive charge (E field radially outward) and negative charge (E field radially inward) both directing in the +ve x direction. So we would expect to see the charge -3/2q3 to the left of P (-x) to cancel the two fields in the +x direction from q1 and q2. We would use Etotal = 1/4πεo { E1 + E2- E3 } = 0 and find the distance x by finding a root. Where E1= q/(0-L)2, E2= q/(2L-L)2, E3=3q/2(x-L)2.

I tried this one a few times just going in loops and don't want to confuse anyone one else. For some reason this question which is a trivial 1D problem is getting me lol. Thanks for your support.
 
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Also confused by your charge notation. Do you mean charge q1=-1.5q, etc?
 
You already have setup the equation correctly (if i understand correctly your three charges are q,-q and -1.5q).

What prevents you from solving the equation for x? You will find two solutions for x is that what confuses you?
 
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