Three girls pull a sled. Determine the acceleration.

AI Thread Summary
Two girls are pulling a sled while a third girl exerts a backward force of 2.0 N. The sled has a mass of 10 kg, and the net force must be calculated to determine its instantaneous acceleration. The discussion highlights the need to consider both horizontal and vertical components of the forces involved. The calculated net force is approximately 14.39 N, leading to an acceleration of 1.439 m/s². The term "instantaneous" refers to the acceleration at a specific moment, acknowledging that forces may not remain constant over time.
Natko
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Homework Statement


Two girls pull a sled across a field of snow, as shown in the diagram. A third girl pulls backward with a 2.0 N force. If the mass of the sled is 10 kg, determine its instantaneous acceleration.
Screenshot (104).png


Homework Equations


F=ma

The Attempt at a Solution


Sorry, I'm stumped.
 
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You want to find the net force on the block. Do you have any ideas about how to work this out?
 
To give some further input:

1) forces (pulling) are vectorial, which means they can be added by "putting them tip on tail". So, the net force is the sum over all forces.
2) Can you somehow determine the horizontal and vertical component of the forces?
 
BOYLANATOR said:
You want to find the net force on the block. Do you have any ideas about how to work this out?

MortalWombat said:
To give some further input:

1) forces (pulling) are vectorial, which means they can be added by "putting them tip on tail". So, the net force is the sum over all forces.
2) Can you somehow determine the horizontal and vertical component of the forces?

Thanks for the tips. I'll try:

Fy=10sin30-10sin40
=-1.428 N
Fx= 10cos30+10cos40-2
=14.32 N
√(Fy2+Fx2)=14.39 N
Θ=tan-1(Fy/Fx)
=5.67
a=F/m
=1.439 m/s2 [5.67 down of left]

Is that correct, or did I mess up somewhere? What does the question mean by "instantaneous?" I know what the word means, but how does it affect this question?
 
Last edited:
Natko said:
Thanks for the tips. I'll try:

Fy=10sin30-10sin40
=-4.28 N

Numerical error in here. The rest of the working looks good
 
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Instantaneous means happening at this instant. It is unlikely that the girls could all pull with constant force in a constant direction for an extended time.
 
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