Time constant for the current through the inductor

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Homework Help Overview

The discussion revolves around determining the time constant for the current through an inductor in a given circuit involving a voltage source, a resistor, and an inductor. The circuit parameters include a voltage of 6 volts, a resistance of 10 ohms, and an inductance of 100 mH.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find the equivalent resistance in the circuit to calculate the time constant. Some participants suggest shorting the voltage supply and removing the inductor to analyze the equivalent resistance at the terminals. There is a discussion about whether the equivalent resistance should be considered as 2R or R/2, leading to different interpretations of the time constant formula.

Discussion Status

The discussion is active, with participants exploring different interpretations of the equivalent resistance and its impact on the time constant calculation. Some guidance has been provided regarding the correct approach to finding the equivalent resistance, but there is no explicit consensus on the final interpretation.

Contextual Notes

Participants are working under the assumption that the switch has been open for a long time before being closed, and they are considering the implications of this setup on the circuit analysis.

syhpui2
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Homework Statement



wjD8Y.png


http://i.imgur.com/wjD8Y.png

In the circuit below, V = 6 volts, R = 10 ohms, L = 100 mH. The switch has been open for a long time. Then, at time t = 0, the switch is closed.



What is the time constant for the current through the inductor?

2L / R


Homework Equations



TAU=l/R

The Attempt at a Solution



I am not sure how do I find the equvialent resistance in this case.
 
Last edited:
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Kill the source (short the voltage supply) and remove the inductor. Find the equivalent resistance at the terminals where the inductor was.

attachment.php?attachmentid=40334&stc=1&d=1319604076.gif
 

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gneill said:
Kill the source (short the voltage supply) and remove the inductor. Find the equivalent resistance at the terminals where the inductor was.

attachment.php?attachmentid=40334&stc=1&d=1319604076.gif


Equvialent resistance is 2r then time constant should be L/2R?

instead of 2L/R?

Thanks
 
syhpui2 said:
Equvialent resistance is 2r then time constant should be L/2R?

instead of 2L/R?

Thanks

Nope. Those two resistors are not in series with respect to the open terminals. So the resistance is R/2. That makes your time constant 2L/R.
 

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