Time it takes for light to travel 54 cm

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Homework Help Overview

The original poster attempts to determine the time it takes for light to travel 54 cm through glycerin, given its index of refraction at a specific temperature. The problem involves concepts from optics and the properties of light in different media.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the speed of light in glycerin and question the interpretation of the index of refraction. Some suggest that the original poster's approach may not be appropriate for this context.

Discussion Status

The discussion includes various interpretations of the problem and attempts to clarify the correct application of equations. Some participants express uncertainty about the original poster's calculations and the relevance of the equations provided.

Contextual Notes

There is a mention of potential confusion regarding the temperature correction and the nature of the equations being used, with some participants noting that one of the equations may pertain to sound rather than light.

crystalspark
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Homework Statement



How do you find the time it takes for light to travel 54 cm through glycerin (index of refraction = 1.470 at 20˚C) in an aquarium?

Homework Equations



These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T) niSinθi=nRSinθR

The Attempt at a Solution



v= 331 m/s + (0.59 m/s/c˚)(20˚C)
v= 331 m/s + 11.8 m/s
v= 342.8 m/s

Δt= 0.54 m ÷ 342.8 m/s = 0.0015752 s

But this isn't the right answer
 
Last edited:
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Your problem says "1.470 at 20˚C" which I would interpret to mean that the speed of light in glycerin, at 20˚C, is 1.470 times the speed in vacuum- which would mean that, since you problem asks about the time at 20 C˚, there would be NO correction for temperature.
That is, the speed of light in glycerine, at 20˚C is just the speed of light in vacuum times 1.47.

If I am misinterpreting that, then what is the "0" point for T? 0˚celsius or (more common) 0˚Kelvin?
 
1. Homework Statement

How do you find the time it takes for light to travel 54 cm through glycerin (index of refraction = 1.470 at 20˚C) in an aquarium?

2. Homework Equations

These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T) niSinθi=nRSinθR

3. The Attempt at a Solution

v= 331 m/s + (0.59 m/s/c˚)(20˚C)
v= 331 m/s + 11.8 m/s
v= 342.8 m/s

Δt= 0.54 m ÷ 342.8 m/s = 0.0015752 s

But this isn't the right answer
 
is the answer : 2.626 x 10^-9 ?
 
cupid.callin said:
is the answer : 2.626 x 10^-9 ?

yes! can you show me how to do it!
 
well i didnt use your first eqn

i used: refractive index = (velocity of light in vacuum = 3 x 10^8) / (velocity of light in vaccum)

find velocity in glycerin and use d=vt
 
crystalspark said:
[
These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T)

That formula might refer to the speed of sound in air.

ehild
 
cupid.callin said:
is the answer : 2.626 x 10^-9 ?

Please do not give answers to homework questions. That is against the PF Rules (see the link at the top of the page).
 
crystalspark said:
1. Homework Statement

How do you find the time it takes for light to travel 54 cm through glycerin (index of refraction = 1.470 at 20˚C) in an aquarium?

2. Homework Equations

These equations might be useful: v= 331 m/s + (0.59 m/s/c˚)(T) niSinθi=nRSinθR

3. The Attempt at a Solution

v= 331 m/s + (0.59 m/s/c˚)(20˚C)
v= 331 m/s + 11.8 m/s
v= 342.8 m/s

Δt= 0.54 m ÷ 342.8 m/s = 0.0015752 s

But this isn't the right answer

Duplicate threads merged. Please take care not to multiple post.
 
  • #10
OH YES! That eqn is for sound!
 

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