Time it takes to hit the ground

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A helicopter traveling upward at 69 m/s drops a package from a height of 500 meters. To determine the time it takes for the package to hit the ground, the equation X = 1/2 at^2 + Vt can be used. The discussion suggests calculating how high the package ascends after release before determining the total drop time. By adding the time taken to reach the peak height to the time taken to fall, the total time until impact can be found. This approach effectively combines both upward and downward motion to solve the problem.
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Homework Statement


A hellicopter traveling upward at 69 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?


Homework Equations


possibly displacement??
v= 69
x=500
a=9.8
t=??


The Attempt at a Solution


do i use
X=1/2 at^2 +Vt ??
 
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SunKissedGal1 said:

Homework Statement


A hellicopter traveling upward at 69 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?


Homework Equations


possibly displacement??
v= 69
x=500
a=9.8
t=??


The Attempt at a Solution


do i use
X=1/2 at^2 +Vt ??

That'd work out just fine.
 
SunKissedGal1 said:

Homework Statement


A hellicopter traveling upward at 69 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?


Homework Equations


possibly displacement??
v= 69
x=500
a=9.8
t=??


The Attempt at a Solution


do i use
X=1/2 at^2 +Vt ??

Figure how high the package goes after being released and then figure how long it takes to drop the total distance and add that to the time it took to go up from 500 and that will be your total time.
 
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