Time to Hit the Ground for Thrown Rock?

AI Thread Summary
A rock is thrown vertically upward at 17.0 m/s from a 60.0 m high building, and the goal is to determine the time it takes to hit the ground. The equations of motion, including v^2 = vinitial^2 + 2a(y - yinitial) and y = Vi*t + ½at², are discussed for calculating the time. Initial calculations using Vf = Vi + a*t yielded an incorrect time of 2.17 seconds, prompting a reevaluation. The correct time to reach the ground, after considering the rock's ascent and descent, is found to be just over 5.5 seconds using both methods. The discussion emphasizes the importance of verifying calculations to avoid mistakes.
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Homework Statement



A rock is thrown vertically upward with a speed of 17.0 from the roof of a building that is 60.0 above the ground. Assume free fall. In how many seconds after being thrown does the rock strike the ground?

Homework Equations



I used v^2 = vinitial^2 + 2a(y - yinitial) to find the speed when it hits the ground. I am trying to find the time and can't seem to locate a good equation to use.
 
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From your initial and final v's, you could get the time with Vf = Vi + a*t.
Or start again and use good old y = Vi*t + ½at².
Best to do it both ways as a check!
 
I used Vf = Vi + a*t with Vf = 38.3, Vi = 17, a = 9.8 and came up with t = 2.17 but that is the incorrect answer for when the rock hits the ground. The rock went up at a starting point of 60m, then came down past 60m to hit the ground.
 
I got a time of just over 5 and a half seconds by both methods. Of course I often make mistakes now - I'm over 60. Show your calc if you want a critique.
 
t = (vf - vi)/a so (38.3-17)/9.8 unless i used the wrong formula
 
Initial v is 17. Final v is -38.3. Difference is 55.3.
 
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