(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 300 kg nonuniform boom, 6.0 m long, is loosely pinned at the pivot at P. A 1000 kg

block is suspended from the end of the boom at A. The boom forms a 30° angle with

the horizontal, and is supported by a cable, 4.0 m long, between points D and B. Point

B is 4.0 m from P, and point D is 4.0 m above P. The center of mass of the boom is at

point C, which is 2.0 m from P. Find the tension in the cable, and the x- and

y-components of the force of the pivot on the boom.

http://img202.imageshack.us/img202/262/50669209.jpg [Broken]

2. Relevant equations

3. The attempt at a solution

I calculated torques clockwise and counterclockwise and set them equal to each other, which are perpendicular so using the weight I solved for the Force perpindicular

(Fw(rod)*cos(30)*2)+(Fw(block)*cos(30)*6) = Ftcos(30)*4,

this gives me the Force of tension in the rope, from which i use to split into its X and Y components, and then I get the incorrect answer.

any help would be appreciated, thanks in advance

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# Homework Help: Torque Equilibrium and Elasticity problem

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