Total work of two blocks

In summary, the problem involves two blocks connected by a light string over a frictionless pulley. The 20.0 N block moves 75.0 cm to the right and the 12.0 N block moves 75.0 cm downward. The total work done on the 20 N block is calculated using the equations w=f*d, f_k=u_k*n, and f_s<=u_s*n with coefficients of static and kinetic friction. The final solution was not provided in the conversation and the asker expressed disappointment in not receiving a timely response.
  • #1
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Homework Statement



Two blocks are connected by a very light string passing over a massless and frictionless pulley . The 20.0 N block moves 75.0 cm to the right and the 12.0 N block moves 75.0 cm downward.

Find the total work done on the 20 N block if [tex]\mu _s\;[/tex]=(coeff. of static friction)=0.500 and [tex]\mu _k \;\;\;\; [/tex]=(coeff. of kinetic friction)=0.325 between the table and the 20 N block.

Homework Equations


[tex]w=f\cdot d[/tex]
[tex] f_k=\mu_k\cdot n[/tex]
[tex] f_s\leq\mu_s\cdot n[/tex]

The Attempt at a Solution


w=[7.5N-(.325)(20N)](.75m)=.75J--wrong.
 
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  • #2
Never mind. I've solved it myself through some careful research and considerable effort. It is unfortunate that no one was able to answer this in time. Perhaps you people want some monetary compensation? Or maybe no one liked my problem. Not particularly hard, is it?
 
  • #3


I would first clarify any potential misunderstandings or ambiguities in the given information. For example, I would confirm whether the 20.0 N and 12.0 N refer to the masses of the blocks or the forces acting on them. I would also clarify the direction of motion for each block and the orientation of the pulley.

Assuming that the given information is correct, I would approach the problem by first calculating the forces acting on each block. For the 20.0 N block, there are three forces to consider: gravity (20.0 N downward), tension in the string (unknown), and friction (unknown). For the 12.0 N block, there are two forces: gravity (12.0 N downward) and tension (unknown).

Next, I would use Newton's second law (F=ma) to determine the acceleration of each block. Since the blocks are connected by a string and moving in opposite directions, their accelerations must be equal in magnitude but opposite in direction.

Once the accelerations are known, I would use the equations for work (W=Fd) and friction (F=μN) to calculate the work done on the 20.0 N block. The work done by friction would depend on whether the block is moving or stationary, so both the kinetic and static coefficients of friction would need to be considered.

In summary, the total work done on the 20.0 N block in this scenario cannot be accurately determined without more information and calculations. I would also consider factors such as the materials and surfaces involved, the angle of the string, and any potential energy changes.
 

1. What is the total work of two blocks?

The total work of two blocks refers to the combined amount of energy required to move both blocks from one position to another. It takes into account the force applied, distance traveled, and any other factors that affect the work done.

2. How is the total work of two blocks calculated?

The total work of two blocks can be calculated by multiplying the force applied to move the blocks by the distance they travel. This is known as the work-energy principle and is expressed as W = F x d.

3. What factors can affect the total work of two blocks?

The total work of two blocks can be affected by various factors such as the weight and mass of the blocks, the surface they are being moved on, and the amount of friction present. Additionally, the angle of the incline or any external forces acting on the blocks can also impact the total work.

4. Why is it important to consider the total work of two blocks?

The total work of two blocks is important because it helps us understand the amount of energy required to move objects and the efficiency of the process. It also allows us to make predictions and calculations for similar scenarios in the future.

5. How can the total work of two blocks be minimized?

The total work of two blocks can be minimized by reducing the force applied or the distance traveled. Additionally, using smoother surfaces or reducing friction can also help decrease the total work required. Finding the most efficient way to move the blocks is key to minimizing the total work done.

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