Total work of two blocks

  • Thread starter james brug
  • Start date
1. The problem statement, all variables and given/known data

Two blocks are connected by a very light string passing over a massless and frictionless pulley . The 20.0 N block moves 75.0 cm to the right and the 12.0 N block moves 75.0 cm downward.

Find the total work done on the 20 N block if [tex]\mu _s\;[/tex]=(coeff. of static friction)=0.500 and [tex]\mu _k \;\;\;\; [/tex]=(coeff. of kinetic friction)=0.325 between the table and the 20 N block.

2. Relevant equations
[tex]w=f\cdot d[/tex]
[tex] f_k=\mu_k\cdot n[/tex]
[tex] f_s\leq\mu_s\cdot n[/tex]

3. The attempt at a solution
w=[7.5N-(.325)(20N)](.75m)=.75J--wrong.
 
Never mind. I've solved it myself through some careful research and considerable effort. It is unfortunate that no one was able to answer this in time. Perhaps you people want some monetary compensation? Or maybe no one liked my problem. Not particularly hard, is it?
 

Want to reply to this thread?

"Total work of two blocks" You must log in or register to reply here.

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving

Top Threads

Top