Calculating the Mass of a Tractor Being Dragged by a Tow Truck on Wet Concrete

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The problem involves calculating the mass of a tractor that can be dragged by a tow truck exerting a force of 10,000 N on wet concrete, with a static friction coefficient of 0.70. The calculation shows that the maximum mass of the tractor is approximately 1457.72 kg. It is noted that this calculation assumes the tractor starts from rest, and a heavier tractor could be moved if it were already in motion due to the lower coefficient of kinetic friction. The solution provided is confirmed to be correct for the scenario described. Understanding the differences between static and kinetic friction is crucial for similar problems.
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Homework Statement


The coefficient of limiting static friction of a rubber tire in wet concrete is 0.70. What mass of tractor, with its brakes locked, can be dragged by a tow truck that can exert a horizontal force of 1.0 * 10^4 N?


Homework Equations


Fnetx = ma

Ff = us*Fn

Fn = m*g

The Attempt at a Solution


10000 / (0.70*9.8) = 1457.72


Is that right??...Help NEEDED:confused:
 
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What you calculated is the maximum mass of a tractor that can be moved, starting from rest on a horizontal surface, by a tow truck. Because the coeff. of kinetic friction is less than that of static friction, a more massive tractor could be pulled if it started with a nonzero speed. NOTE: I am just nitpicking the question, your solution seems fine to me.
 
oo so thaz rite??
 
yes, good.
 

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