Town clock seconds hand speed and centripetal acceleration

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SUMMARY

The speed of the tip of the second hand on a town clock, which has the same length as the minute hand, is calculated to be 0.00816 m/s, derived from the ratio of their rotation speeds. The centripetal acceleration of the second hand is determined using the formula aradial = -v²/r, resulting in a value of 0.00067 m/s². These calculations utilize the total acceleration equation atotal = sqrt(a² radial + a² tangential), where tangential acceleration is negligible for uniform circular motion.

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  • Understanding of circular motion and angular velocity
  • Familiarity with the concepts of speed and acceleration
  • Knowledge of basic physics equations related to motion
  • Ability to manipulate equations involving variables such as radius and velocity
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  • Study the principles of angular velocity and its relationship to linear speed
  • Learn how to derive centripetal acceleration from linear velocity
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  • Practice solving problems involving rotational dynamics and acceleration
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gap0063
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1. (a)The speed of the tip of the minute hand on a
town clock is 0.00136 m/s.
What is the speed of the tip of the second
hand of the same length?
Answer in units of m/s.

(b)What is the centripetal acceleration of the tip
of the second hand?
Answer in units of m/s2.



Homework Equations


atotal = sq rt (a2 radial + a2 tangential) where aradial = −v2/r and atangential = d|v|/dt


The Attempt at a Solution


I have no idea how to start this... I just think I need to use those equations
 
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gap0063 said:

Homework Equations


atotal = sq rt (a2 radial + a2 tangential) where aradial = −v2/r and atangential = d|v|/dt


The Attempt at a Solution


I have no idea how to start this... I just think I need to use those equations
Your relevant equations only deal with acceleration. But anyway, as a place to start, what is the length of the minute hand?
 

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