Transfer Function: Magnitude and Phase of Complex Function

AI Thread Summary
To find the magnitude and phase angle of the complex function f(s) = 1/(1+s)^2, the substitution s = jω is appropriate. By substituting this into the function, the expression simplifies to f(jω) = 1/(1+jω)^2. The resultant form indicates that the function has a quadratic pole, and the magnitude and phase can be derived from this expression. The phase angle can be calculated using the arctangent of the imaginary part over the real part, while the magnitude is the absolute value of the complex function. This approach confirms that setting σ to zero is correct for evaluating f(jω).
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Homework Statement



f(s) = f(\sigma + j\omega) = \frac{1}{(1+s)^2}

Find the magnitude and phase angle of f(j\omega)

Homework Equations



s = j\omega is a substitution you can make, but I'm not sure if you are supposed to apply that here

The Attempt at a Solution



I tried substituting \sigma + j\omega into the function and applying s = j\omega.

Then I get

\frac{1}{(\sigma + 1)^2 + 2s(\sigma + 1) + s^2}

I have a feeling it's supposed to be a quadratic pole, but the form of this doesn't match the form of a quadratic pole exactly.
 
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If they ask for f(jw) and they give you f(σ + jw) then σ = 0. So yes, let s = jw and proceed.
 
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