Transfer Function of Block Diagram

AI Thread Summary
The discussion revolves around deriving the transfer function for a PM DC servo motor with current loop feedback. Participants are attempting to simplify the block diagram and factor the resulting transfer function, which initially appears as G(s) = Kt / (JLs² + J(R + Ki)s + KtKb). There is a focus on the conditions for Ki that allow for an approximation of the transfer function as G(s) = (1/Kb) / (τms + 1)(τes + 1). Despite efforts to apply the quadratic formula and factor the denominator, participants express difficulty in arriving at the expected form of the transfer function. The conversation highlights the challenges in achieving the desired result while exploring potential typos or alternative approaches.
ThLiOp
Messages
8
Reaction score
0

Homework Statement


The block diagram of a PM DC servo motor with current loop feedback is shown below:

QWERTY.jpg


If Ki is adjusted such that J(Ki+R)2 >> 4KTKbL, show that the transfer function may be approximated by

G(s) = (1/Kb) / (τms+1)(τes+1),

where

τm = J(R+Ki) / KTKb

τe = L / (R+Ki)

The Attempt at a Solution


[/B]
I simplified the block diagram and got the transfer function:

G(s) = Kt / (JLs2 + J(R + Ki)s + KtKb)

Then I tried to factor the denominator. When using the quadratic formula, I found:

(-JR - JKi) +/- sqrt( J[ J(R+Ki)2 - 4KtKbL]) / 2JL

Assuming the conditions presented for Ki, I canceled out the 4KtKbL.

Am I on the right path? In the end, I still couldn't get the transfer function presented in the homework.
 
Physics news on Phys.org
ThLiOp said:
I simplified the block diagram and got the transfer function:

G(s) = Kt / (JLs2 + J(R + Ki)s + KtKb)
That seems fine.

ThLiOp said:
Then I tried to factor the denominator. When using the quadratic formula, I found:

(-JR - JKi) +/- sqrt( J[ J(R+Ki)2 - 4KtKbL]) / 2JL
Those are just the roots, though. If ##ax^2 + bx + c## is your polynomial, then its factored form is ##a(x - x_1)(x - x_2)##, where ##x_1## and ##x_2## are its roots.

ThLiOp said:
Am I on the right path? In the end, I still couldn't get the transfer function presented in the homework.
I can't either. Going your route, and I think the approximation shown is highly suggestive of that, I get the form:
$$
\frac{\dot{\theta}(s)}{V(s)} = \frac{\frac{1}{K_b}}{\tau_m s (\tau_e s + 1)}
$$
Sort of looks like a typo, but maybe there's another route I'm just not seeing.
 
Back
Top