Translational and Rotational Energy

AI Thread Summary
The discussion centers on the relationship between translational and rotational energy in a sliding cylinder. It highlights that an initial blow can impart both rotation and sliding motion, with friction eventually slowing the sliding while allowing the rotation to enhance translational velocity. There is confusion regarding how friction affects energy, with a concern that it might reduce both rotational and translational speeds. The conversation indicates a need for clarity on the dynamics of sliding versus non-slipping objects. Understanding these principles is essential for grasping the mechanics involved in such scenarios.
hatephysics
Messages
9
Reaction score
0
solved. thank you
 
Last edited:
Physics news on Phys.org
Well, if the initial blow imparted a sizeable rotation, AND the cylinder was sliding on the ground, (while rotating) eventually the sliding would slow due to the friction with the ground and the cylinder's rotation could contribute to its translational velocity.
 
AEM said:
Well, if the initial blow imparted a sizeable rotation, AND the cylinder was sliding on the ground, (while rotating) eventually the sliding would slow due to the friction with the ground and the cylinder's rotation could contribute to its translational velocity.

Thank You for taking the time to reply.

But, I still don't quite get this. Wouldn't the friction cause the cylinder to have less energy and, therefore, a slower cylinder rotation and a slower translational velocity? Maybe, it is because I don't quite understand rotations involving objects that slide? Currently, I am only dealing with objects that do not slip.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top