Trial function and Eigenfunction....

Ronf
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Homework Statement


Hello, I just started to study QM, I just have a general question, how to know if a trial function is not an eigenfunction of a hamiltonian (that has the lowest value in a graph) ? - Thanks and sorry for the stupid question.

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The Attempt at a Solution


I have an idea, but I am not sure if it is right. Is the trial function a eigenfuction of a hamiltonian, if it gives a value (lowest) which is very close to the ground-state energy? [/B]
 

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Ronf said:
how to know if a trial function is not an eigenfunction of a hamiltonian (that has the lowest value in a graph) ?
It is not when the corresponding expectation value of energy does not match any of the eignvalues of the Hamiltonian.
Ronf said:
Is the trial function a eigenfuction of a hamiltonian, if it gives a value (lowest) which is very close to the ground-state energy?
Again, if this value is not exactly the same as one of the Hamiltonian's eigenvalues, then the tried function is not an eigenfunction.
 
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Thank you man, I really appreciate your help, much love to you. :smile:
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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