- #1
aisha
- 584
- 0
Hi just need a little help with the behaviour of this trig function
[tex] y=-3\cos (2x-\frac {\pi} {6}) +1 [/tex]
I converted the pi over 6 to degrees and got -30
need to state the period, amplitude, max/min values, range, domain, horizontal phase shift, and vertical dispacement.
So far after rearranging the the equation i have
period= [tex] pi [/tex]
range= ?
amplitude=?
domain= all values XER
horizontal phase shift= 15 degrees left
vertical displacement= up 1
max\min ? not sure how to figure this out from the equation i tried graphing using the graphing calculator but it won't give me the values for max and min. Therefore I cannot solve for amplitude yet and same with range.
CAN SOMEONE PLEASE HELP ME JUST NEED HELP WITH THE MAX AND MIN THANKS
[tex] y=-3\cos (2x-\frac {\pi} {6}) +1 [/tex]
I converted the pi over 6 to degrees and got -30
need to state the period, amplitude, max/min values, range, domain, horizontal phase shift, and vertical dispacement.
So far after rearranging the the equation i have
period= [tex] pi [/tex]
range= ?
amplitude=?
domain= all values XER
horizontal phase shift= 15 degrees left
vertical displacement= up 1
max\min ? not sure how to figure this out from the equation i tried graphing using the graphing calculator but it won't give me the values for max and min. Therefore I cannot solve for amplitude yet and same with range.
CAN SOMEONE PLEASE HELP ME JUST NEED HELP WITH THE MAX AND MIN THANKS