Trigonometric inequality problem.

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Homework Help Overview

The discussion revolves around a trigonometric inequality involving the expression \( \frac{1+\sin(x)}{5+4\cos(x)} \). Participants are tasked with deducing that this expression lies within the bounds of 0 and \( \frac{10}{9} \) for all values of \( x \).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the possibility of graphing the expression to visualize its behavior. Questions are raised about the conditions under which the denominator may be zero or negative. There are suggestions to find critical points to determine maximum and minimum values, as well as a proposed method to prove the inequality by manipulating the expression.

Discussion Status

The discussion is active, with participants offering various approaches to tackle the problem. Some guidance has been provided regarding the analysis of the expression, including suggestions to check the denominator and explore critical points. Multiple interpretations of the inequality are being discussed, but no consensus has been reached.

Contextual Notes

Participants are considering the implications of the denominator being zero or negative, which may affect the validity of their approaches. There is also an emphasis on proving the inequality through algebraic manipulation, indicating a focus on rigorous justification.

Michael_Light
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Homework Statement



Deduce that 0 ≤
MSP154219h2f53c89aa97ch00001f2200631f7c6f1g.gif
≤ 10/9 for all values of x.

Homework Equations


The Attempt at a Solution



Is it possible to sketch a graph for
MSP154219h2f53c89aa97ch00001f2200631f7c6f1g.gif
? How?

Or is there any methods to find the max./min. value of
MSP154219h2f53c89aa97ch00001f2200631f7c6f1g.gif
?

Please enlighten me...
 
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is the denominator ever zero or negative? if not try mutiplying through by it

or find the critical points to fiind max and min
 
If you can prove [itex]1+sin(x)-\frac{10}{9}(5+4cos(x))[/itex] is always less than 0, you can get the less than part. If you think about the numerator, the greater than part also follows quickly.
 

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