Triple integral in spherical coordinates.

In summary: Axler.Definitely. I do not know many good free books that go in depth the way that introductory books should, so unfortunately you will have to either pay for these texts or find them at a local library. There are a few introductory calculus books that are good. One is "Calculus" by Spivak. Another is "Vector Calculus, Linear Algebra, and Differential Forms" by Hubbard. "Calculus on Manifolds" by Spivak is a good second choice. "Linear Algebra Done Right" by Axler is also a good book. "Linear Algebra Done Wrong" by Axler is not as good, but it does cover some topics that are not in "Lin
  • #1
102
3
While deriving the volume of sphere formula, I noticed that almost everyone substitute the limits 0 to 360 for the angle (theta) i.e the angle between the positive x-axis and the projection of the radius on the xy plane.Why not 0to 360 for the angle fi (angle between the positive z axis and radius)?
I tried it, but I got 0 as answer.Please explain this.
 
Physics news on Phys.org
  • #2
Think about the Earth using latitude and longitude. Latitude runs from 90 degrees north latitude (the North Pole) to 90 degrees south. So that's 180 degrees. Longitude runs from 0 to 180 East longitude and then from 180 West longitude back to 0. So that's 360 degrees.

If you let latitude run a full 360 degrees, then points on Earth would have multiple coordinates: The point that is 270 degrees south of the North Pole and longitude 0 is the same as the point that is only 90 degrees south of the North Pole and longitude 180.
 
  • #3
stevendaryl said:
Think about the Earth using latitude and longitude. Latitude runs from 90 degrees north latitude (the North Pole) to 90 degrees south. So that's 180 degrees. Longitude runs from 0 to 180 East longitude and then from 180 West longitude back to 0. So that's 360 degrees.

If you let latitude run a full 360 degrees, then points on Earth would have multiple coordinates: The point that is 270 degrees south of the North Pole and longitude 0 is the same as the point that is only 90 degrees south of the North Pole and longitude 180.
Iam not suggesting to make both latitude and longitude 360.My question is,
why shouldn't we let latitude run 360 and make longitude 180?
Just inverting the system.
 
  • #4
Mohankpvk said:
Iam not suggesting to make both latitude and longitude 360.My question is,
why shouldn't we let latitude run 360 and make longitude 180?
Just inverting the system.
There is no problem doing that. However, the volume element is then different: you can calculate it using classical geometry or using the Jacobian of your new coordinate system. If you integrate the old volume element using your new coordinate system, what you are integrating will no longer represent volume.
In particular, recall that the ##r\sin \phi ## factor of the volume element ##r^2 \sin\phi \, dr\, d\theta\, d\phi ## comes about geometrically from the length of the projection of the radial position vector of each point onto the xy-plane in order to get the sweeping radii for the lengths of arc ##d\theta ## and ##d\phi ##. If you are now allowing ##\phi ## to have values above 180°, then ##r\sin \phi ## will be a negative number when ##180^{\circ} < \phi < 360^{\circ}##. We do not want those projection lengths to be negative, so that is not the standard volume element anymore.
To get the correct standard volume, you can use the factor ##r|\sin \phi |## instead, which would result in a volume element of ##r^2 |\sin\phi | \, dr\, d\theta\, d\phi ##. However, I think you can see that this is a bit unwieldy.
 
  • Like
Likes Mohankpvk
  • #5
slider142 said:
There is no problem doing that. However, the volume element is then different: you can calculate it using classical geometry or using the Jacobian of your new coordinate system. If you integrate the old volume element using your new coordinate system, what you are integrating will no longer represent volume.
In particular, recall that the ##r\sin \phi ## factor of the volume element ##r^2 \sin\phi \, dr\, d\theta\, d\phi ## comes about geometrically from the length of the projection of the radial position vector of each point onto the xy-plane in order to get the sweeping radii for the lengths of arc ##d\theta ## and ##d\phi ##. If you are now allowing ##\phi ## to have values above 180°, then ##r\sin \phi ## will be a negative number when ##180^{\circ} < \phi < 360^{\circ}##. We do not want those projection lengths to be negative, so that is not the standard volume element anymore.
To get the correct standard volume, you can use the factor ##r|\sin \phi |## instead, which would result in a volume element of ##r^2 |\sin\phi | \, dr\, d\theta\, d\phi ##. However, I think you can see that this is a bit unwieldy.
Thank you.Nice answer.
Is there any good(and simple,introductory) books for calculus and vector calculus?
 
  • #6
Mohankpvk said:
Thank you.Nice answer.
Is there any good(and simple,introductory) books for calculus and vector calculus?
Definitely. I do not know many good free books that go in depth the way that introductory books should, so unfortunately you will have to either pay for these texts or find them at a local library.

The best introductory textbook path I know to calculus and vector calculus is to first go through "Calculus" by Spivak, then study the texts "Vector Calculus, Linear Algebra, and Differential Forms" by Hubbard, "Calculus on Manifolds" by Spivak, "Linear Algebra Done Right" by Axler, and "Linear Algebra Done Wrong" by Treil concurrently.

The first is a nice walkthrough introduction of vector calculus that showcases many applications as well as showing details of vital theorems. The second gives an extremely bird's eye view of vector calculus that takes you from the basic component-based vector approach to the modern exterior calculus coordinate-independent approach with proper proofs and rigor. The latter two books help fill out the rigor in your understanding of linear algebra, as much of vector calculus is concerned with reducing nonlinear problems to questions in linear algebra. Knowing how linear algebra works properly is thus an important skill. Hope this helps you out! :-)
 
  • Like
Likes Mohankpvk
  • #7
slider142 said:
Definitely. I do not know many good free books that go in depth the way that introductory books should, so unfortunately you will have to either pay for these texts or find them at a local library.

The best introductory textbook path I know to calculus and vector calculus is to first go through "Calculus" by Spivak, then study the texts "Vector Calculus, Linear Algebra, and Differential Forms" by Hubbard, "Calculus on Manifolds" by Spivak, "Linear Algebra Done Right" by Axler, and "Linear Algebra Done Wrong" by Treil concurrently.

The first is a nice walkthrough introduction of vector calculus that showcases many applications as well as showing details of vital theorems. The second gives an extremely bird's eye view of vector calculus that takes you from the basic component-based vector approach to the modern exterior calculus coordinate-independent approach with proper proofs and rigor. The latter two books help fill out the rigor in your understanding of linear algebra, as much of vector calculus is concerned with reducing nonlinear problems to questions in linear algebra. Knowing how linear algebra works properly is thus an important skill. Hope this helps you out! :-)
Thank you
 

Suggested for: Triple integral in spherical coordinates.

Replies
5
Views
3K
Replies
5
Views
1K
Replies
3
Views
2K
Replies
2
Views
862
Back
Top