Evaluate the triple integral for the function [itex]\int\int\int y dV[/itex] over that part of the cube 0 [itex]\leq[/itex] x,y,z [itex]\leq[/itex] 1 lying above the plane y +z = 1 and below the plane x+y+z = 2
The Attempt at a Solution
This is the first attempt at a triple integral problem. The method I have been taught is to reduce the integral to a double integral problem by first integrating over the region perpendiculr to some base.
When I try to draw this thing, it seems like it's a half a cube, or a triangular prism, with a little bit cut off one corner. But I can't seem to find a base perpendicular to some dimmension that is bound by two simple functions. it seems that part of the object is bound by x =1, y =1, z = 1 and part by one of the other functions.
I am really lost..