Trouble Understanding Phasor to Time Domain Conversion Math

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SUMMARY

The discussion centers on the conversion from phasor to time domain, specifically addressing an arithmetic discrepancy in the equation provided in the textbook. The correct expression for the current is identified as i(d, t) = 0.20 cos(ωt + βd + 159◦) - 0.091 cos(ωt − βd + 185.6◦), highlighting the necessity of a minus sign for the second term. Participants agree that the textbook contains an error regarding the sign of the coefficient for the second cosine term. This consensus reinforces the importance of careful verification in mathematical conversions.

PREREQUISITES
  • Understanding of phasor representation in electrical engineering
  • Familiarity with trigonometric functions and their properties
  • Basic knowledge of time-domain analysis
  • Proficiency in arithmetic operations involving angles in degrees
NEXT STEPS
  • Study the principles of phasor analysis in electrical circuits
  • Learn about time-domain conversion techniques in signal processing
  • Explore common errors in textbook examples related to phasors
  • Review trigonometric identities and their applications in engineering
USEFUL FOR

Electrical engineering students, educators teaching signal processing, and professionals involved in circuit analysis will benefit from this discussion.

Mark Zhu
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Homework Statement
See image attachment
Relevant Equations
I(d, t) = Re[I (d) e ^ jωt]
This is a problem about converting from the phasor to time domain. I am having trouble following the math that the textbook is doing.
I was thinking the final answer should be:
i(d, t) = 0.20 cos(ωt + βd + 159◦) - 0.091 cos(ωt − βd + 185.6◦)
emphasize the minus 0.091 instead of plus 0.091 as shown in the image attachment and textbook.
Am I missing something here? Thank you.
 

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Looks like it should be a minus sign. My arithmetic also gives me ## -.090 ##.
 
Thank you, I also consulted with someone else and we thought the textbook had made an error as well.
 
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