Trouble with particular solution of differential equation - rewrite my answer?

cowmoo32
Messages
121
Reaction score
0
Trouble with particular solution of differential equation - [SOLVED]

Homework Statement


Find the particular solution of the differential equation
c995a54ca48d21f6dc81446bdd54881.png

satisfying the initial condition
907c69d9098d2e376491d1dfd7f0771.png



The Attempt at a Solution


[STRIKE]I end up with (1/2)ln(-x^2+10x) which does satisfy the initial conditions, yet it's coming back as incorrect. Is there another way I can write the formula?[/STRIKE]

I figured it out, check post #3
 
Last edited:
on Phys.org
cowmoo32 said:

Homework Statement


Find the particular solution of the differential equation
c995a54ca48d21f6dc81446bdd54881.png

satisfying the initial condition
907c69d9098d2e376491d1dfd7f0771.png



The Attempt at a Solution


I end up with (1/2)ln(-x^2+10x) which does satisfy the initial conditions, yet it's coming back as incorrect. Is there another way I can write the formula?
Show how you got the result you show. I assume you mean y = (1/2)ln(-x2 + 10x).

Satisfying the initial conditions is not enough: the solution has to satisfy the differential equation, too.
 
Scratch that above, I had a negative out of place. See below. I corrected it and it's coming back as correct.

[itex]\frac{dy}{dx}[/itex]=e-2x(x-5)

[itex]\int[/itex] (e2y)dy = [itex]\int (x-5)dx[/itex]

e2y = x2 - 10x + C

2y = ln(x2 - 10x + C)

C = 50
 
Last edited:

Similar threads

Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K