Trying to differentiate using function of a function/Chain rule

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Homework Help Overview

The problem involves differentiating the function y = (cos 2x)³ using the chain rule, which is a method for differentiating composite functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the chain rule by defining u = cos 2x and differentiating accordingly. They express uncertainty about their final answer and seek validation from others.

Discussion Status

Some participants provide feedback on the original poster's differentiation steps, with one confirming the approach appears correct while another points out a minor error in notation. The discussion reflects a collaborative effort to clarify the differentiation process.

Contextual Notes

The original poster indicates repeated attempts at solving the problem, suggesting a struggle with the application of the chain rule. There is an emphasis on accuracy in notation and understanding of the differentiation process.

Mike2793
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Homework Statement



Using the function of a function formula differentiate the following:

y = (cos 2x)3

Homework Equations



dy/dx = dy/du * du/dx

The Attempt at a Solution



y = (cos 2x)3

u = cos 2x
y = u3

dy/du = -2sin2x
du/dy = 3u2

dy/dx = dy/du * du/dx

dy/dx = -2sin2x * 3(cos2 2x)

= -6sin2x cos22x

Hi, I've been racking my brain over this question for sometime now, I've attempted it multiple times getting it wrong over and over again. I've got this answer, but, I'm really not confident that it is right. Can you guys take a look at it and work some magic? It's function of a function, which I think is more commonly known as the Chain rule.

Thank you.
 
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That looks right to me.
 
Seriously?

I'm speechless!
 
Mike2793 said:
dy/du = -2sin2x
du/dy = 3u2
should read as:
\frac{dy}{du} = 3u^2 and
\frac{du}{dx} = -2\sin 2x
but other than that, it looks fine.
 
Haha, there's my attention to detail. Thanks very much, guys, I can finally lay this to rest.
 

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