Trying to understand two masses connected by a shaft

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anon6912
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I have the following system I got from a book, which models the dynamics of two masses connected by a shaft.

The system is given below:
Schematic of two rotating masses joined by a shaft: an LP_A turbine (M2, D2) on the left and a generator (M1, D1) on the right, with shaft stiffness K12, torques T23, T12 and Te, speeds w0, w1, w2, and angles δ1 and δ2 measured from the nominal rotating reference.


And the equations given in the book for this system is below:
Typed equations of motion for a generator rotor and an LPA turbine section, listing input, output and damping torques and the resulting differential equations for speed deviation and angle.


The nominal speed is w0.
And the interest here is the deviations from the nominal for mass 1 (Δw1) and mass 2 (Δw2).

I understand all the equations except for the ones below:

Equation d(δ1)/dt = (Δω1) ω0, where δ1 is the angle, Δω1 the speed deviation of mass 1 and ω0 the nominal speed.

Equation: d δ2 / dt = (Δω2) ω0, where δ2 is the angle of mass 2, Δω2 is its speed deviation and ω0 is the nominal speed.


How does it make sense that the rate of change of the angle equates to the deviation in speed for that mass times the nominal speed?
bc331d30-a574-408f-ba6c-0a3d7a71e20b
 
Attachments
  • Schematic of two rotating masses joined by a shaft: an LP_A turbine (M2, D2) on the left and a generator (M1, D1) on the right, with shaft stiffness K12, torques T23, T12 and Te, speeds w0, w1, w2, and angles δ1 and δ2 measured from the nominal rotating reference.
    hTqu6ml.png
    5.8 KB · Views: 966
  • Typed equations of motion for a generator rotor and an LPA turbine section, listing input, output and damping torques and the resulting differential equations for speed deviation and angle.
    krHiOa9.png
    21.4 KB · Views: 890
  • Equation d(δ1)/dt = (Δω1) ω0, where δ1 is the angle, Δω1 the speed deviation of mass 1 and ω0 the nominal speed.
    tEjMpK8.png
    1 KB · Views: 538
  • Equation: d δ2 / dt = (Δω2) ω0, where δ2 is the angle of mass 2, Δω2 is its speed deviation and ω0 is the nominal speed.
    oM2Li72.png
    945 bytes · Views: 534
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I can't answer your question, but just judging by the notations involved, I'd guess that you got this from an EE textbook. The generally make a hash of rotor dynamics. By the time everything is expressed in "per unit," nothing makes sense anymore.
 
anon6912 said:
How does it make sense that the rate of change of the angle equates to the deviation in speed for that mass times the nominal speed?
bc331d30-a574-408f-ba6c-0a3d7a71e20b
Quite - it makes no sense dimensionally.