Two blocks and a pulley, friction

AI Thread Summary
The discussion revolves around a physics problem involving two masses connected by a string over a frictionless pulley, with one mass on a horizontal surface experiencing kinetic friction. The user struggles to incorporate the effect of friction, given the coefficient of kinetic friction is 0.2, while attempting to find the acceleration of the system. They initially used the equation a = (mBg)/(mA + mB) without considering friction. Responses suggest reevaluating the tension in the string and recognizing that both masses influence the system's dynamics. The conversation highlights the importance of accounting for friction in calculating the acceleration accurately.
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Homework Statement



Two masses are connected by a string which passes over a frictionless, massless pulley. One mass hangs vertically and one slides on a horizontal surface. The horizontal surface has a coefficient of kinetic friction 0.2. The vertically hanging mass is 4.0 kg and the mass on the horizontal surface is 6.0 kg. Find the acceleration of the mass.

Homework Equations



T=mBg-mBa

The Attempt at a Solution



I've basically done this problem without factoring friction, and this my problem, I don't know how to factor friction.

a = (mBg)/(mA + mB) is what I used.


Thanks!
 
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nbaumann said:

Homework Statement



Two masses are connected by a string which passes over a frictionless, massless pulley. One mass hangs vertically and one slides on a horizontal surface. The horizontal surface has a coefficient of kinetic friction 0.2. The vertically hanging mass is 4.0 kg and the mass on the horizontal surface is 6.0 kg. Find the acceleration of the mass.

Homework Equations



T=mBg-mBa

The Attempt at a Solution



I've basically done this problem without factoring friction, and this my problem, I don't know how to factor friction.

a = (mBg)/(mA + mB) is what I used.


Thanks!
Welcome to Physics Forums,

You should look again at the tension in the string, is that the only condition that the tension needs to satisfy? What about the other block?
 
Thanks for your reply.

This was really as far as I got. Wouldn't the tension just apply once? As there is only one string?
 
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