Two Dimensional Kinematics of an electron

chloe99
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Homework Statement



An electron in a cathode-ray tube is traveling horizontally at 2.60×109 cm/s when deflection plates give it an upward acceleration of 5.90×1017 cm/s^2.What is its vertical displacement during this time?

Homework Equations





The Attempt at a Solution


I got this one but other than that I am so lost How long does it take for the electron to cover a horizontal distance of 6.10 cm? t =2.35×10^-9s
 
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Where did the 6.10 cm come from?
 
It was given to me in the original problem.
 
Wait, I'm confused. I don't see it in the problem you posted.

In fact, the problem as you posted it is incomplete. It talks about "vertical displacement during this time" but there's no time given. Why don't you post the problem again but make sure to include the whole thing this time :wink:
 
Oops...I am sorry about that.

An electron in a cathode-ray tube is traveling horizontally at 2.60×109 cm/s when deflection plates give it an upward acceleration of 5.90×1017 cm/s^2. What is its vertical displacement during this time?
 
chloe99 said:
Oops...I am sorry about that.

An electron in a cathode-ray tube is traveling horizontally at 2.60×109 cm/s when deflection plates give it an upward acceleration of 5.90×1017 cm/s^2. What is its vertical displacement during this time?
Isn't that the same thing you posted before, though?

Sorry to not be helpful, but I'm really confused by what you're posting.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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