Two masses hanging from a pulley (conservation of energy)

AI Thread Summary
The discussion revolves around a physics problem involving two masses connected by a string over a frictionless pulley, focusing on the conservation of energy to find the speed of the 22.5 kg mass when it hits the ground. Participants emphasize the importance of considering both gravitational potential energy (PE) and kinetic energy (KE) in the system, including the rotational kinetic energy of the pulley. There is a debate about how to account for the energy transformations, particularly how the gravitational PE of the elevated mass converts into KE of both masses and the pulley. The need to establish relationships between the different forms of KE is highlighted, as is the clarification that the mass on the ground does not possess PE at the moment of impact. The conversation concludes with a call to formulate an energy equation that accurately represents the initial and final states of the system.
khannon5
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Homework Statement


Two masses are connected by a string that hangs over a frictionless pulley with mass 8kg, radius .25m, and moment of inertia .5mr^2. One mass lays on the ground and has mass 15kg. The other mass is 22.5 kg and is 2.75 m above the ground. Use conservation of energy to determine the speed of the 22.5 kg mass when it hits the ground

Homework Equations


Ke final = pe initial
Ke=.5mv^2 + .5Iw^2

The Attempt at a Solution


I found the pe of the 22.5 mass using pe=mgh. I made that equal the ke equation but I'm not sure whether to combine masses or what to use
 
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The system loses gravitational PE. The first question is to ask where does this energy go?
 
There are three elements to the system, the two masses and the pulley. Consider the total energy (KE and PE) of each at start and again at the moment of impact.
 
PeroK said:
The system loses gravitational PE. The first question is to ask where does this energy go?
Kinetic energy of each mass and the rotation of the pulley
 
khannon5 said:
Kinetic energy of each mass and the rotation of the pulley

Can you write down an energy equation involving all the energies gained and lost?
 
PeroK said:
Can you write down an energy equation involving all the energies gained and lost?
Ke=.5mv^2 of mass 1 + .5mv^2 of mass 2 + .5Iw^2 of pulley
 
khannon5 said:
Ke=.5mv^2 of mass 1 + .5mv^2 of mass 2 + .5Iw^2 of pulley

OKay, but there's no PE there.

You're also going to have to find a relationship between the various KE's. So, you need to think about that as well.
 
PeroK said:
OKay, but there's no PE there.

You're also going to have to find a relationship between the various KE's. So, you need to think about that as well.
Would the pe just be the mgh of the weight above the ground?
 
khannon5 said:
Would the pe just be the mgh of the weight above the ground?

There are two masses involved.
 
  • #10
PeroK said:
There are two masses involved.
But why does it have pe if it's on the ground
 
  • #11
khannon5 said:
But why does it have pe if it's on the ground

Does it stay on the ground?
 
  • #12
PeroK said:
Does it stay on the ground?
No but in the beginning it has no pe
 
  • #13
khannon5 said:
No but in the beginning it has no pe
Right (assuming ground is taken as the reference point for PE). So post the initial energy = final energy equation.
 
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