Two objects colliding & sticking together, what is their final speed?

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In a collision between two freight cars, each with a mass of 2.5 x 10^5 kg, one car moving at 3.4 m/s collides with another at rest, resulting in a completely inelastic collision where they stick together. The conservation of momentum principle is applied, leading to the equation m1v1 + m2v2 = (m1 + m2)v', where v' is the final speed. By substituting the known values, the final speed can be calculated. The solution emphasizes the importance of using momentum conservation to find the final velocity after the collision. The final speed of the combined freight cars can be determined through this method.
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Homework Statement



Two freight cars, each with a mass of 2.5 multiplied by 10^5 kg, collide and stick together.
One was initially moving at 3.4 m/s and the other was at rest. What is their final speed?


Homework Equations


m(vf-vi)


The Attempt at a Solution


(2.5*10^5)(0-3.4)= -850,000
= -8.5 * 10^5 m/s
 
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The main thing you can use in the problem is conservation of momentum:

m1v1+m2v2=(m1+m2)v'

This equality is a result of the completely inelastic collision. The question asks you to solve for v'.
 
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