(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two blocks are connected by a rope that passes around two pulleys as indicated in the figure. (Attached)

a. Determine the tension in the rope.

b. Determine the acceleration of each block (Hint: The two blocks do not have the same acceleration).

3. The attempt at a solution

I call m1 the left mass and m2 the right.

I think the Tension is the same for the whole rope.

My m1 free body has normal up (+y) weight down, kinetic friction left, Tension right (+x)

My m2 free body is 2T up (-y) and weight down.

I think a1=2a2

For m1x Fx=max

T-f=m1a

T=2ma2+um1g

For m2:

m2g-2T=m2a2

T=(m2g-m2a2)/2

I put my two equations together to eliminate T

4m1a2+2um1g=m2g-m2a2

I solved for a2

a2=(m2g-2um1g)/(4m1+m2)

I plugged what I had for a2 into the original to solve for u:

I ended up with m2g-2um1g-m2g=2um1g

everything cancels to -u=u

Can someone please point out my flaw, be it in my algebra or my logic?

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# Homework Help: Two Pulleys, Two Masses

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