1. The problem statement, all variables and given/known data Two blocks are connected by a rope that passes around two pulleys as indicated in the figure. (Attached) a. Determine the tension in the rope. b. Determine the acceleration of each block (Hint: The two blocks do not have the same acceleration). 3. The attempt at a solution I call m1 the left mass and m2 the right. I think the Tension is the same for the whole rope. My m1 free body has normal up (+y) weight down, kinetic friction left, Tension right (+x) My m2 free body is 2T up (-y) and weight down. I think a1=2a2 For m1x Fx=max T-f=m1a T=2ma2+um1g For m2: m2g-2T=m2a2 T=(m2g-m2a2)/2 I put my two equations together to eliminate T 4m1a2+2um1g=m2g-m2a2 I solved for a2 a2=(m2g-2um1g)/(4m1+m2) I plugged what I had for a2 into the original to solve for u: I ended up with m2g-2um1g-m2g=2um1g everything cancels to -u=u Can someone please point out my flaw, be it in my algebra or my logic?