Uncharged spherical conducting shell

AI Thread Summary
An uncharged spherical conducting shell surrounds a charge of -q at its center, and when a charge of +3q is placed outside the shell, the charges on the inner and outer surfaces become +q and -q, respectively. The +3q charge does not influence the total charge on the exterior surface but affects the distribution of charge on the shell. According to Gauss's Law, the electric field depends only on the charge enclosed, which in this case is -q. Thus, the outer charge does not alter the inner charge's effect on the shell. Understanding these principles is crucial for analyzing charge distribution in electrostatics.
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An uncharged spherical conducting shell surrounds charge -q at the center of the shell. Then a charge+ +3q is placed on the outside of the shell. When static equilibrium is reached, the charges on the inner and outer surfaces of the she are respecteively... +q,-q is the answer.

Does the +3q charge play any roll in that answer? Help. Thanks!
 
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VU2 said:
An uncharged spherical conducting shell surrounds charge -q at the center of the shell. Then a charge+ +3q is placed on the outside of the shell. When static equilibrium is reached, the charges on the inner and outer surfaces of the she are respecteively... +q,-q is the answer.

Does the +3q charge play any roll in that answer? Help. Thanks!

Do you know Gauss's Law ?
 
Yes, its E=q/[ε*area], where q is the charge enclosed.
 
VU2 said:
Yes, its E=q/[ε*area], where q is the charge enclosed.

That should give you your answer.
 
So +3q charge doesn't play any roll at all right?
 
VU2 said:
So +3q charge doesn't play any roll at all right?

That is correct, as far as the total charge on the exterior. However,the +3q does affect the distribution of that charge.
 
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