I think since the drive force F is applied at an oblique angle, the author thought it would be clearer to the student to decompose this force into its horizontal and vertical components, and work out the reactions and bending moments created by each component separately.pinkcashmere said:can someone explain why this problem would involve two bending moment diagrams, one for the xy plane and another for the xz plane?
The same equations of static equilibrium apply in each case. The author has resolved F into its components on the overhung end of the shaft. There are two bearings where reactions develop. Write the standard sum of the forces and sum of the moment equations for each case and solve for the unknown reactions.Also, how are the reaction forces at B and C determined each time?
SteamKing said:I think since the drive force F is applied at an oblique angle, the author thought it would be clearer to the student to decompose this force into its horizontal and vertical components, and work out the reactions and bending moments created by each component separately.
Both moment arms are the same distance from the bearing at C, namely 100 mm.pinkcashmere said:So the F_r component for example, it generates a moment about the xy plane because it has a moment arm to the xy plane? But doesn't it also have a moment arm to the yz plane?