Understanding Capacitor Networks: 120+(-60), 30+(-90)

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Homework Help Overview

The discussion revolves around understanding a capacitor network with specific charge values indicated as 120+(-60) and 30+(-90). Participants are trying to clarify how to determine the charge distribution across the capacitor plates and the implications of shorting a switch in the circuit.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the clarity of the problem statement and the source of the charge values. There is a focus on how to interpret the charge distribution and the flow of charge when the switch is shorted. Some suggest treating the network as two parallel networks and using the formula Q=VC to compute charges.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and attempting to clarify the assumptions made about the circuit. Some guidance has been offered regarding calculating equivalent capacitance and charge distribution, but no consensus has been reached.

Contextual Notes

There are indications of unclear diagrammatic representation and potential miscommunication regarding the problem's wording. Participants are also reflecting on the implications of equilibrium in the circuit and the absence of current flow under certain conditions.

herich
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Your diagram is rather unclear. I don't see any voltmeter. Where is it supposed to be?
 
herich said:
How can I know the top 2 plates are +60 and below are -60?
120+(-60) and 30+(-90)?
And how can I fill in the blanks~?

The statement of the problem is incorrect and I will assume it is sloppy wording, because after equilibrium is reached, there is no current flowing anywhere in the circuit with no restive path between the terminals of the battery.

But taking the awkward wording as meaning they want to know the total flow of charge as a result of shorting the switch, I have to ask where it is you got the figures for the charges on the capacitors before or after the switch is shorted?

Please show your work as to how you arrived at those figures at the points x and y.
 
Actually there are the figures deduced from my friend's tutor.
But I know that first we can treat the network as two parallel networks, and the two sides of the capacitors can simply computed by using the formula Q=VC.

I just doubt how <+60>and <-60> can be found out. And how to deduce in what way the charge will flow.
 
herich said:
Actually there are the figures deduced from my friend's tutor.
But I know that first we can treat the network as two parallel networks, and the two sides of the capacitors can simply computed by using the formula Q=VC.

I just doubt how <+60>and <-60> can be found out. And how to deduce in what way the charge will flow.

Why don't you start out then by calculating the equivalent capacitance of each leg. Then you will know the first part of what you need - the charge on each capacitor - and hence the voltage at each node.

Then you proceed to calculate the equivalent capacitance of the new network after the short is affected. Armed with that you can calculate the effective new charges and then you can describe the difference.
 

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