Understanding Hinge Reactions: Debunking Common Misconceptions

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SUMMARY

This discussion clarifies the distinction between the normal reaction and the hinge reaction in mechanics, specifically in the context of tension and forces acting on a system. Participants emphasize that the normal reaction acts perpendicular to the wall, while the hinge reaction is influenced by the direction of forces such as Tsin60 and gravitational forces (15g). The confusion arises from the definition of positive direction in force resolution, which can lead to different interpretations of the equations involved. Ultimately, the correct interpretation is that the hinge reaction must be upwards when considering the moments about point B.

PREREQUISITES
  • Understanding of basic mechanics principles, including tension and normal forces.
  • Familiarity with vector resolution of forces in two dimensions.
  • Knowledge of torque and moments in static equilibrium.
  • Ability to interpret free-body diagrams accurately.
NEXT STEPS
  • Study the concept of normal forces in static equilibrium scenarios.
  • Learn how to resolve forces in two dimensions using vector components.
  • Explore the principles of torque and how to calculate moments about a pivot point.
  • Review examples of hinge reactions in various mechanical systems.
USEFUL FOR

Students and professionals in engineering, particularly those focusing on mechanics, static equilibrium, and structural analysis. This discussion is beneficial for anyone looking to clarify their understanding of forces acting on structures involving hinges.

Svelte1
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Homework Statement
https://postimg.cc/JtP2h113
Relevant Equations
f=ma
https://postimg.cc/JtP2h113
243800

I think I may have forgotten some more basic elements of tension and normal reactions. I do not understand why the vertical component of the normal reaction =Tsin60-15g

Because Tsin60-15g is negative when resolving upwards, i would have thought this meant that the normal vertical reaction would have to be upwards so that that we would have 0 acceleration
 
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Svelte1 said:
why the vertical component of the normal reaction =Tsin60-15g
You mean the reaction at the wall, not the normal reaction. (By definition, the normal reaction would be at right angles to the wall.)
Whether it is Tsin60-15g or 15g-Tsin60 depends on which way you are defining as positive. Tsin60-15g is right if down is positive.
 
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haruspex said:
You mean the reaction at the wall, not the normal reaction. (By definition, the normal reaction would be at right angles to the wall.)
Whether it is Tsin60-15g or 15g-Tsin60 depends on which way you are defining as positive. Tsin60-15g is right if down is positive.

In the books workings it says they are resolving vertically upwards and clarifies that it is indeed the reaction at the hinge:
https://postimg.cc/Wtn5VyxJ
 
Svelte1 said:
that it is indeed the reaction at the hinge:
Yes, reaction at the hinge, not normal reaction.

The book is wrong about the direction. If you take moments about B, both weights have a clockwise torque, so the hinge reaction must be upwards.
 
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