Understanding Integrals: A Challenging Problem in Calculus

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Yesterday in class a professor give us this problem:

X= integral of 3du


This is my first year in the university, and I don't know anything about integrals, I have tried to solve it, but I can not find the result... the correct result. It was like a "brain shock" for me, because the professor doesn't explain nothing, just give us that.
Also, I don't know english, and I don't know if somebody could help me.

Thank you anyway...
 
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The problem is x= \int{3du}. So, how would you integrate a constant?

This might help if I change the variables to x, y which you're probably more accustomed to seeing. y= \int{3dx}
 
An integral is like asking you for an anti-derivative. So that question is basically asking you the antiderivative of 3 with respect to x, which is _____________?
 
Welcome to PF!

vdfortd said:
An integral is like asking you for an anti-derivative. So that question is basically asking you the antiderivative of 3 with respect to x, which is _____________?

Hi Manzanita! Welcome to PF! :smile:

In case you don't understand "anti-derivative", that means that you are looking for a function y(x) such that dy/dx = 3. :smile:
 
Wow!

Thank you :D

I was really [I don't know how to explain it...] "problemous... problematic?" [sorry my english is not very well indeed...]

I have seen the answers and I have understand [reading my book and this topic].

Thank you very much ^^


PD: Muchas gracias de veras :D!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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