nikphd
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Hello,
We know that surface integrals come to the form of a surface integral of a scalar function over a surface and a vector field over a surface. First one is \oint F(x,y,z)d{S} and the second one is \oint \vec{F}(x,y,z)\cdot d\vec{S}=\oint \vec{F}(x,y,z)\cdot \vec{n}dS, where n is the unit normal vector of surface S.
Lately, I've seen integrals of the form \oint \vec{p}dp, over p, where p is a unit vector. I fail to understand the meaning of that, is it surface integral of scalar or vector function? There is no dot product if its a vector function, so what am i missing here?
We know that surface integrals come to the form of a surface integral of a scalar function over a surface and a vector field over a surface. First one is \oint F(x,y,z)d{S} and the second one is \oint \vec{F}(x,y,z)\cdot d\vec{S}=\oint \vec{F}(x,y,z)\cdot \vec{n}dS, where n is the unit normal vector of surface S.
Lately, I've seen integrals of the form \oint \vec{p}dp, over p, where p is a unit vector. I fail to understand the meaning of that, is it surface integral of scalar or vector function? There is no dot product if its a vector function, so what am i missing here?