Understanding the Electrical Field Lines of a Charged Insulating Disk

AI Thread Summary
The discussion focuses on sketching the electric field lines of a uniformly charged insulating disk, emphasizing the behavior of these lines both close to and far from the disk. Near the center, field lines are nearly perpendicular to the surface, while they curve outward as one moves away from the center. At a distance, the disk behaves like a point charge, with lines radiating outward. The conversation also addresses the implications of the disk being an insulator versus a conductor, noting that in an insulator, charge remains on one side, while in a conductor, it spreads uniformly across the surface. Understanding these concepts is crucial for accurately representing the electric field lines in electrostatics.
tongpu
Messages
21
Reaction score
0

Homework Statement


Sketch the electrical field lines of a uniformly charged insulating disk. Show field lines close and far away.


Homework Equations


none, conceptual


The Attempt at a Solution


For close to the surface of disk near the center the field lines are almost perpendicular to surface, as you move away from center the field line curves away. For the curve part of the disk the field lines point outwards.

For far away the disk is like a pint charge so the field lines point away from the disk.

No charge is given so how can i tell, and how does knowing in an insulator the electrons do not move freely help? What if it is a conductor?
 
Physics news on Phys.org
tongpu said:

Homework Statement


Sketch the electrical field lines of a uniformly charged insulating disk. Show field lines close and far away.


Homework Equations


none, conceptual


The Attempt at a Solution


For close to the surface of disk near the center the field lines are almost perpendicular to surface, as you move away from center the field line curves away. For the curve part of the disk the field lines point outwards.

For far away the disk is like a pint charge so the field lines point away from the disk.

Although you have no picture here to help see what you mean, your verbal description sounds basically correct.

No charge is given so how can i tell, and how does knowing in an insulator the electrons do not move freely help? What if it is a conductor?

In electrostatics problems, when no charge is specified, the convention is to describe the behavior for positive charge. (It is understood that the field direction would be reversed for negative charge.)

I suspect that, since the problem specifies an *insulating* disk, they are asking you to treat the charge as being on only *one* side of the disk. (For an "ideal" insulator, it would all *stay* there.) For an "ideal" conductor, the charge would spread itself over the entire surface as uniformly as possibly, so (nearly) half the total charge would be on either side. (We can neglect the thickness of the disk in an introductory physics problem.)
 
Is this over 2D or 3D? If the charge is uniformly distributed... then the field lines are going to be radially outward from the center of the disk.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top