Understanding the Relationship of Sphere Coordinates and Rotations

AI Thread Summary
The discussion focuses on the relationship between the coordinates of a sphere's center (X, Y, Z) and its orientations (alpha, beta, gamma) while rolling on a fixed sphere. It highlights that a sphere has six degrees of freedom (DOF) in space, but when rolling, it effectively has three DOF due to the relationship between coordinates and rotations. Key equations are provided to describe the contact point and the rolling motion, including the relationship between angular velocities. Clarifications on the terms used, such as the distinction between angular velocity vectors phi and omega, are also discussed. The conversation emphasizes the complexities of understanding rotational dynamics in this context.
hmoein
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hi , every one!
I have a problem with a sphere rolling on a fixed sphere. My problem is to find relationship between coordinate of center of sphere (X,Y,Z) and orientations (alpha, beta, gamma) or Euler angles of sphere. as we know a sphere has 6 DOF in space (3 coordiantes and 3 rotation) when a sphere rolling on surface we expect that it have 3 dof beacuse of relation beween coordinate and rotation.
for example when a circle roll on a surface the x coordinate of its center is:
X=R*teta (R = radius of circle) and it has one DOF.
Like the circle rolling i want to find the relations for sphere.
thanks
hossein
 
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Hi
for a sphere of center C and radius R rolling on a fixed sphere centered at origin with radius 1 you have (using polar reference)

- a relation for contact: C = (1+R) e_{r}
- relation for rolling without sliding: \dot{C} = R * \phi \times e_{r},

where \dot{C} = (1+R) \omega \times e_{r} (the latter is the time derivative of the first eq.),

and where e_{r} describe the versor pointing the moving ball center, \phi is the moving ball angular velocity (or displacement) and \omega the angular velocity (or displacement) related to e_{r} through the relation \dot{e_{r}} = \omega \times e_{r}.

Then the ball has 3 free DOF, \omega and \phi_{//}=\phi \cdot e_{r}, with

d \phi_{\bot}=d \omega (1+R)/R.

Look to the attached mathematica file for teh simpler case of circle rolling on circle (1 free DOF).

M
 

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hi drMs
thanks for your answer. i don't understand about \\time e_{r}. and what is difference between \\phi and \\omega?
could you expalin more?
best regard
hossein
 
Hi-
\times means vector product. \phi is the (free) angular velocity vector describing the rotation of the ball. \omega is the (free) angular velocity vector describing the rotation of the versor e_{r} (which I used for the lagrangian parameters of the moving ball center).

M
 
thank you very much
 
Hi drMs
suppose that the moving sphere is in contact with th efixed one at one contact point.
is the rotattion about the z axis (axis that is perpendicular to the contact surface and pass through center of sphere ) rolling?
 
Hi
It is not really clear to me the question. You mean the spin motion (rotation of the ball with rotation vector parallel to the segment connecting the two centers)?
 
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