Understanding Velocity Direction in Basic Physics Equations

AI Thread Summary
Understanding the direction of velocity in physics equations is crucial, particularly when dealing with falling objects. In the discussed scenario, a hot-air balloon drops a compass, and the correct velocity direction must be negative to indicate downward motion. While calculations may yield positive values, the context of the problem dictates that falling objects have negative velocity. The appropriate equation to determine the time for the compass to hit the ground involves using s = s_0 + v_0 t + 1/2 a t^2, leading to a quadratic solution for time. Correctly identifying the sign of velocity is essential for accurate problem-solving in physics.
duki
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Hey all,


I was wondering if someone could explain how to tell whether V = - or +?

I'm getting answers right using the formula

V^2 = sqrt(Vo^2 + 2ay)

but I'm getting positive answers. How do you tell whether the velocity is in the + or - direction?


Sample Question:

A hot-air balloon is rising upward with a constant speed of 2.50m/s. When the balloon is 3.00m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?


I got V = 8.1m/s but the right answer requires using -8.1m/s.

thanks for any help :)
 
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They expect you to know that a falling object hits the ground with negative (downward) velocity!

Both answers are consistent with the given initial conditions of acceleration and velocity. But only one of those answers is the one you're looking for. The other answer is the velocity the object would have to leave the ground with to end up 3 m high with the given speed. (In other words: What goes up, comes down. :wink: )
 
ah ok. that makes since... thanks!
 
hi,

i saw the thread and wanted to know how we would actually go about answering the questions it asks. I figured out how to solve the problem but I can't figure out how many seconds it would take for the compass to drop. please help.

thanks,

Z
 
deuceszbigz said:
I figured out how to solve the problem but I can't figure out how many seconds it would take for the compass to drop.
What have you figured out so far?
 
i basically have the same example, but the values given to me are different. the problem i have is:

A hot-air balloon is rising upward with a constant speed of 2.20 m/s. When the balloon is 3.50 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?

i was able to solve as far as the other student, but then I get stuck. any suggestions?
 
The best equation for you to use is

s = s_0 + v_0 t + 1/2 a t^2

Solving for t is then a quadratic. (Why does this topic have so many views?)
 

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