Understanding Work and Energy: Solving a Physics Problem

AI Thread Summary
The discussion revolves around solving a physics problem involving an object sliding to a stop due to friction. The user is trying to find the coefficient of kinetic friction after determining the forces at play and the object's acceleration. There is confusion regarding the correct application of equations and the role of mass, which is not provided in the problem. Participants emphasize the importance of correctly substituting values and understanding the relationship between forces and energy. The conversation highlights the need to analyze the equations and consider kinematic principles to simplify the problem without needing the mass.
kixtoby
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Misplaced homework moved here by moderator, hence no template.
I have been stuck on this physics question:

An object is sliding along a flat surface with an initial speed of 30 m/s. What must the coefficient of kinetic friction be between the object and the surface if the object slides to a stop in 10m? What would be the speed of the object after it had only slide half that distance?

So I know that uk = Fk/FN
and that Fd = 1/2mv(initial)^2
but for the life of me I cannot figure out how to solve this problem.

Any help at all would be extremely appreciated.

I have done this:
F(10m)=1/2(9.8m/s2)(30m/s)
F(10m)=147m/s
F=14.7m/s

Am I at least on the right track?
 
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kixtoby said:
and that Fd = 1/2mv(initial)^2

kixtoby said:
I have done this:
F(10m)=1/2(9.8m/s2)(30m/s)

Be careful in the substitution. Do it again. Also what are you trying to find by this?
 
QuantumQuest said:
Be careful in the substitution. Do it again. Also what are you trying to find by this?
I am honestly not sure, I guess what I was trying to find was the force? But I need to find the coefficient of kinetic friction between the object and the floor. I guess I'm not sure what direction I need to go to solve this.
 
kixtoby said:
I am honestly not sure, I guess what I was trying to find was the force? But I need to find the coefficient of kinetic friction between the object and the floor. I guess I'm not sure what direction I need to go to solve this.

Is the substitution you do correct? Please check it again
 
QuantumQuest said:
Is the substitution you do correct? Please check it again
I noticed I forgot to square...was that my only error? I also was not sure about plugging in gravity, but no mass was given in the problem...
F(10)=1/2(9.8)(30)^2
F(10)=4410
F=441
 
kixtoby said:
I noticed I forgot to square...was that my only error? I also was not sure about plugging in gravity, but no mass was given in the problem...

Squaring is second. First, you have substituted g for mass. This is wrong. Now, if m is not given, can you think of a way to not have it in your equation?
 
QuantumQuest said:
Squaring is second. First, you have substituted g for mass. This is wrong. Now, if m is not given, can you think of a way to not have it in your equation?
Find a way to cross it out?
 
kixtoby said:
Find a way to cross it out?

Cancelling is one way. What can you do and what can you find?
 
What is the acceleration of the object? Have you drawn a free body diagram?
 
  • #10
Chestermiller said:
What is the acceleration of the object? Have you drawn a free body diagram?
how would I calculate acceleration from the information given? And yes, I did draw one, although I wasn't really sure what values to plug in...
 
  • #11
QuantumQuest said:
Cancelling is one way. What can you do and what can you find?
Can I multiply mass on each side to cancel them out? Then the equation would be: fd=1/2v^2
 
  • #12
kixtoby said:
Can I multiply mass on each side to cancel them out?

I don't understand this. Can you elaborate writing the equation?

EDIT: As a hint, what does the initial equation you wrote express in words?
 
  • #13
kixtoby said:
Can I multiply mass on each side to cancel them out? Then the equation would be: fd=1/2v^2
What is f? Previously you used F for force. If f is the same, the left hand side is energy, while right hand side is velocity-squared. That would be dimensionally impossible.
Relate FN to mass.
 
  • #14
QuantumQuest said:
I don't understand this. Can you elaborate writing the equation?
Original
haruspex said:
What is f? Previously you used F for force. If f is the same, the left hand side is energy, while right hand side is velocity-squared. That would be dimensionally impossible.
Relate FN to mass.
I am very lost. I don't think I understand this problem at all.
 
  • #15
kixtoby said:
Original

Original?

EDIT: Try to analyze the equation. What does it express? What can you substitute and what can you find from it in order to proceed to the solution of the problem?
 
  • #16
kixtoby said:
Original

I am very lost. I don't think I understand this problem at all.
What are the vertical forces? What is the vertical acceleration? If m is the mass, what equation does that give you?
 
  • #17
QuantumQuest said:
Original?

EDIT: Try to analyze the equation. What does it express? What can you substitute and what can you find from it in order to proceed to the solution of the problem?
Sorry, I didn't realize I had replied to you. I started to type and must have hit reply by mistake.
So for this problem, I know that friction does work: f*d which is is equal to the initial kinetic energy (1/2)mv^2
Then, F = mu * mg where my goal is to solve for mu (coefficient of kinetic friction).

I am still not understanding how to go about this without knowing the mass. Is there another hint you could give me? I almost think I am making this harder than it needs to be, but I just don't understand.
 
  • #18
Are you familiar with the SUVAT equations for a body moving with constant acceleration? If so, which one do you think you can you use in this problem to calculate the acceleration of the object (This part of the calculation does not involve Newton's laws. It is totally kinematic)?
 
  • #19
kixtoby said:
f*d which is is equal to the initial kinetic energy (1/2)mv^2
Then, F = mu * mg where my goal is to solve for mu (coefficient of kinetic friction
Do F and f stand for the same thing here? If so, why not connect those two equations, eliminating it? If not, what are they?
 
  • #20
kixtoby said:
I am still not understanding how to go about this without knowing the mass. Is there another hint you could give me?

Look at what haruspex asked in #19. You have to understand which force's work is f*d - as you write it, in your initial equation. Also, I recommend looking at it the way Chestermiller suggests in #18.
 
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