OK, except for a decimal mistake in one of your numbers.bumblebeeliz said:We square them and then do we subtract them? Which would equal to:
(1.4 x 106 m/s)2 - (3.5x104 m/s)2
(1.96 x 1012 m2/s2) - (1.22x108 m2/s2)
No. How did you get this? (What's 1012 - 108? To subtract, rewrite the numbers so they have the same exponent.)(1.95878 x 104 m2/s2 )
Not when you are subtracting the numbers. Look what happens if you do:bumblebeeliz said:I thought we could subtract the exponent.
102 - 101 = 10x101 - 1x101 = (10-1)x101 = 90I am not sure how to re-write the numbers and make them have the same exponent.
Not sure what you mean by "factoring". Here's the trick. If you reduce the exponent by 1, then you must increase the number by a factor of 10 (since this is base 10). Which just means move the decimal point to the right by 1.bumblebeeliz said:I see what you mean, but I am really not sure how to apply it in my situation. I basically factor it?
When you divide two numbers, then you can just subtract the exponents. But you're subtracting two numbers.I looked at some resources online and somebody suggested to divide them to allow the subtraction:
1.4 x 1012 / 3.5 x 108 = 0.4 x 104
Careful. That "/2" shouldn't be there.bumblebeeliz said:One more question:
1.95978 x 1012/ 0.02
97.989 x 1012 /2
No. The exponent doesn't change; just divide the numbers:bumblebeeliz said:Sorry, I meant this below: (scratch the first line)
97.989 x 1012 /2
48.969 x 1011
The formula for calculating (1.4 x 106 m/s)2 - (3.5x104 m/s)2 is (v1^2) - (v2^2), where v1 and v2 are the respective velocities in meters per second.
The unit of measurement for the result of this calculation is meters squared per second squared (m2/s2).
Squaring the velocities before subtracting ensures that the result is a positive value, as both velocities are squared in the formula. This also allows for a more accurate representation of the difference in velocities.
This formula can be used for any type of velocity, as long as the units are consistent. For example, if the velocities are in miles per hour, the result will be in square miles per hour squared (mi2/h2).
Calculating the difference between two velocities is important in many scientific fields, such as physics and engineering. It allows for the comparison and analysis of motion, and can provide valuable information about the speed and direction of an object.