Unraveling the Mystery of Neutrons in Fission Reactions

AI Thread Summary
The fission reaction involving uranium-235 illustrates the role of neutrons in initiating and sustaining a chain reaction. A free neutron is essential on the left side of the equation as it triggers the fission process. The reaction produces additional neutrons, which can further induce more fission events. This mechanism is crucial for the operation of nuclear reactors, where maintaining a controlled chain reaction is vital. Understanding the presence of the neutron is key to grasping the dynamics of nuclear fission.
mandy9008
Messages
127
Reaction score
1

Homework Statement


Fission reaction:
10n + 23592U --> 14156 + 9236 Kr + 3(10n)

Why in the world is there a neutron on the left side of this rxn? Why not just reduce the number of neutrons on the right side to two?
 
Physics news on Phys.org
Mathematically that would make sense, but physically the way the equation is written is the way it actually happens. A free neutron CAUSES the fission in a reactor and frees several neutrons which go on to cause other fissions - a chain reaction.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top