Using Hooke's law to find the pull back distance?

AI Thread Summary
The discussion focuses on using Hooke's Law to determine the pull back distance of a slingshot for propelling an object. It clarifies that while the force is calculated using F = ma, the pull back distance directly affects the force exerted by the slingshot, as described by F = -kx. As the pull back distance increases, the force also increases, leading to greater acceleration of the object when released. This results in a higher speed upon leaving the slingshot, allowing the object to travel further. Therefore, the pull back distance is crucial for achieving the desired propulsion distance.
grover1213
Messages
2
Reaction score
0

Homework Statement


I'm given the mass of the object and acceleration (gravity), and I'm given the pull back distance of one test of the slingshot. I've found the k constant by finding force with f=ma, but I need to find the pull back distance using the same slingshot in order to propel the object a certain distance. My question is that because the distance seems to have no effect on the force, (because it is only mass times acceleration), if I solved for the pull back distance with the force, wouldn't I get the same pull back distance that i used with the first equation?


Homework Equations


F=-kx


The Attempt at a Solution

 
Physics news on Phys.org
You will have to be more specific about the problem statement. Since F = kx, as you pull back the slingshot more, x increases, so therefore, F increases. And since F_net = ma, since F is now larger when you pull the slingshot back, then the object in the sling will accelerate more during its period of contact with the sling, until it leaves it. And since it accelerates more, then it's speed will be higher when it leaves the sling, and will travel a greater distance. hcceleration of the object in the slingshot is not the acceleration of gravity in either case.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top