Using Newtons 2nd law for rotational motion

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SUMMARY

This discussion focuses on applying Newton's 2nd law for rotational motion to a system of massless pulleys. The law is expressed as dL/dt = torque, where L represents angular momentum. Participants clarify that while the pulleys lack angular momentum, the forces in the strings create moments about the pulleys' centers. By writing out the torque equations for the pulleys, one can derive the necessary relationships between wire tensions.

PREREQUISITES
  • Understanding of Newton's 2nd law for rotational motion
  • Familiarity with angular momentum concepts
  • Basic knowledge of torque and its calculations
  • Experience with pulley systems and tension forces
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  • Study the derivation of torque equations in rotational dynamics
  • Explore examples of massless pulley systems in physics
  • Learn about the relationship between tension and angular momentum
  • Investigate advanced applications of Newton's laws in rotational systems
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Physics students, educators, and engineers interested in understanding the dynamics of rotational motion and pulley systems.

gralla55
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I've attached an image explaining the problem. All pulleys are massless. Basically, they want me to show some relations between wire tensions, using Newtons 2nd law for rotational motion.

This law is written in my book as:

dL / dt = torque, where L is angular momentum.

I'm not sure exactly how to do that. Since there is no mass in the pulleys, they shouldn't have any angular momentum. And if they don't, how can I apply this law for anything? Or perhaps they just want me to state that since the pulleys are clearly falling straight down (no lateral movement), the string tensions on each end of each pulley has to be equal to each other?

Any help here would be very appreciated!
 

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Although the pulleys themselves have no angular momentum, the forces in the strings have moment about the centres of the pulleys. If you write out the torque equations for the pulleys you should get the desired answers.
 

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