Engineering V1 = 2V Calculate Voltage, Power in Circuit w/ Inductor at t=>0

[freezer]

Homework Statement

For the circuit shown below, the current through the inductor is defined as follows:

<br /> i(t)=\begin{cases}<br /> 0 &amp; \text{if } -\infty &lt;t&lt;0 \\ <br /> 1-e^{-2t}&amp; \text{if } 0\leq t &lt; \infty <br /> \end{cases}<br />

L = 1H, R2 = 2 ohms

For t=> 0 find:

a) VL(t)
b) Vr(t)
c) V1(t)
d) Power absorbed by the inductor

Homework Equations

<br /> i(t)=\frac{v}{R}(1-e^{-Rt/L})<br />

The Attempt at a Solution

As t goes to infinity, current goes to 1A and the inductor becomes a wire. So V1 = 2V

But i don't think this is what it is asking for.
From the relevant equation section, solving for V would leave only 2

W = 0.5Li^2

W = 0.5(1)(1-e^{-2t})^2

Vr = (1-exp(-2t))/2

Vl = 0V

 

[Simon Bridge]

Looks like it wants t→0 ... for very small times, the exponential term is approximately linear.